See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  f b k k A B fast     2 K B C slow  By writing steady state approximation for ‘B’     f b 2 d B k A k B k B 0 dt         f b 2 k A B k k   Now, rate  2 k B     2 f b 2 k k A r k k    So,   2 f b 2 k k k k k         2 0.1