When excess toluene-α-d (C6H5CH2D) was photochemically monochlorinated at 80°C with 0.1 mole of chlo — Chemical Kinetics Chemistry Question
Question
When excess toluene-α-d (C6H5CH2D) was photochemically monochlorinated at 80°C with 0.1 mole of chlorine, there was obtained 0.0212 mole DCl and 0.0848 mole $HCl$. What is the value of the isotope effect, K^H / K^D?
Answer: B
💡 Solution & Explanation
The photochemical monochlorination of toluene-α-d (C6H5CH2D) involves the abstraction of either H or D. The ratio of the products formed is $HCl$ formed / DCl formed = 0.0848 mol / 0.0212 mol = 4. Therefore, the overall isotope effect (neglecting statistical factors for the number of H and D atoms as per the book's options) is K^H / K^D = 4.
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