See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1: Identify the parent ring. The structure shows a five-membered carbocyclic ring, so the parent chain is cyclopentane. Step 2: Identify the substituents and functional groups on the ring. - There is an exocyclic double bond (=CH2, methylidene) attached to one carbon of the ring. - There is a bromine (Br) on an adjacent carbon. - There is a hydroxyl group (OH) on the next carbon. - There is a chlorine (Cl) on a carbon two positions away from the OH. Step 3: Assign the principal characteristic group. The hydroxyl group (-OH) is the principal characteristic group, so the compound is named as a cyclopentanol. Step 4: Number the ring to give the principal characteristic group (OH) the lowest possible locant. Assign C1 to the carbon bearing OH. Step 5: Number around the ring to give the remaining substituents the lowest set of locants consistent with the OH at C1. - C1: OH - C2: Br (bromine) - C3: =CH2 (methylidene, exocyclic double bond) - C4: (unsubstituted CH2) - C5: Cl (chlorine) Step 6: Name the exocyclic double bond. An exocyclic =CH2 group on a ring carbon is named as 'methylidene' (or 'methylene'), giving the suffix '-3-methylidenecyclopentanol' (or using 'ylidene' nomenclature). The ring carbon bearing the =CH2 is C3, so this is 3-methylidenecyclopentanol as the base. Step 7: Assemble the full IUPAC name by listing substituents alphabetically: bromo (C2), chloro (C5), methylidene (C3). Full name: 2-bromo-5-chloro-3-methylidenecyclopentanol. No other options are presented to eliminate, but any alternative numbering would give higher locant sets for the principal characteristic group or substituents, so this numbering is correct. Therefore, the correct answer is 2-bromo-5-chloro-3-methylidenecyclopentanol.