JEE Mains Chemistry Past PapershardNUMERICAL

For a reaction X + Y = 2Z, 1.0 mol of X, 1.5 mol of Y and 0.5 mol of Z were taken in a 1L vessel andJEE Mains Chemistry Past Papers Chemistry Question

Question

For a reaction X + Y = 2Z, 1.0 mol of X, 1.5 mol of Y and 0.5 mol of Z were taken in a 1L vessel and allowed to react. At equilibrium, the concentration of Z was 1.0 mol L–1. the equilibrium constant of the reaction is ………… x . The value of x is ……. Ans

💡 Solution & Explanation

x + y 2z t=0 1 mol 1.5 mol 0.5 mol Since moles of Z are increased at equilibrium therefore reaction goes in forward direction to attain the equilibrium. x + y 2z t=teq 1-a 1.5 - a 0.5 + 2a = 1 mole  a = 0.25 x + y   2z . mol . mol mol keq = ] y [] x [ ]z [ = X ] . 1[ . 1   X = ) . 75 . (  = 16

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