CuSO4 + 2NaOH(excess) -> Cu(OH)2↓ + Na2SO4 — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Identify the reactivity of the metal hydroxide. Copper(II) hydroxide, Cu(OH)2, is a basic hydroxide that is insoluble in water. Step 2: Observe the reaction with excess NaOH. Unlike amphoteric hydroxides (like Zn(OH)2 or Al(OH)3), copper(II) hydroxide is not amphoteric and does not dissolve in excess sodium hydroxide. Step 3: Consequently, the copper(II) hydroxide precipitate remains in the mixture, classifying the process as a precipitate formation reaction (type A). Thus, the correct option is (a).