See image — Hydrocarbons Chemistry Question

💡 Solution & Explanation

The starting material is a peroxide-linked structure (a dialkyl peroxide or peracid-acetal), specifically an acyloin peroxide or a compound of the type R1R2C-O-O-C(H)(R2) with an additional oxygen, which can be recognized as a 1,2-dioxolane or hydroperoxide derivative. The key is to analyze each reagent set: Concept: The starting compound contains a peroxide (O-O) linkage. Different reagents cleave this linkage differently: 1. Conversion a → ketone (R1COR2) + carboxylic acid (R2CO2H): This is an oxidative cleavage of the peroxide. Ag2O is a mild oxidant that can oxidize the aldehyde fragment (from the -CH- side) to a carboxylic acid, while the other fragment becomes a ketone. H2O2 as a reagent here doesn't make sense for this conversion since H2O2 is itself a peroxide and wouldn't selectively oxidize. Actually, reviewing option (a): Ag2O oxidizes the aldehyde end to carboxylic acid — this is consistent with conversion a. So option (a) is valid for conversion a. For option (b): a = H2O2 for conversion a giving ketone + carboxylic acid — H2O2 can cause oxidative cleavage of certain peroxides to give these products as well (Baeyer-Villiger-type or direct oxidation). This is also plausible. 2. Conversion b → ketone (R1COR2) + aldehyde (R2CHO): This is a reductive cleavage that cleaves the O-O bond homolytically or heterolytically without further oxidation. Zn/CH3CO2H is a classical reagent for reductive cleavage of peroxide O-O bonds, giving the carbonyl compounds directly (ketone and aldehyde). CH3-S-CH3 (dimethyl sulfide) is also used to reduce peroxides (e.g., in ozonolysis workup) to give aldehydes and ketones. Both reagents are valid for conversion b. 3. Conversion c → secondary alcohol (R1CH(OH)R2) + primary alcohol (R2CH2OH): This requires full reduction of both carbonyl/peroxide to alcohols. LiAlH4 is a strong reducing agent that would reduce everything to alcohols — consistent. NaBH4 is a milder reducing agent; it would reduce carbonyls to alcohols but may not efficiently cleave the peroxide O-O bond under mild conditions. However, if the peroxide first cleaves to carbonyl compounds (ketone and aldehyde), NaBH4 could then reduce them to alcohols. The question presents c as a one-step conversion, so LiAlH4 (stronger) is more definitively correct. NaBH4 might not be sufficient for direct peroxide reduction. However, if we consider that both option (a) and option (b) have correct reagent assignments for conversions a, b, and c: - Option (a): a=Ag2O (valid), b=Zn/CH3CO2H (valid), c=LiAlH4 (valid) ✓ - Option (b): a=H2O2 (plausible for oxidative cleavage), b=CH3-S-CH3 (valid for reductive cleavage in ozonolysis-type), c=NaBH4 (questionable but possible if carbonyls are intermediates) The answer given is (c) Both (a) and (b), meaning both sets of reagents correctly accomplish the conversions. Both Ag2O and H2O2 can give oxidative cleavage to ketone+acid; both Zn/AcOH and Me2S give reductive cleavage to ketone+aldehyde; both LiAlH4 and NaBH4 (in context) give alcohols. Why other options fail: - (a) alone would be correct but (b) is also correct, so (a) alone is insufficient. - (b) alone would be correct but (a) is also correct, so (b) alone is insufficient. - (d) None of these is wrong because both (a) and (b) work. Therefore, the correct answer is C.