Radiations of frequency v are incident on a photosensitive metal. The maximum kinetic energy of photoelectrons is E. When the frequency of the incident radiations is doubled, what is the maximum kinet

Question

Radiations of frequency v are incident on a photosensitive metal. The maximum kinetic energy of photoelectrons is E. When the frequency of the incident radiations is doubled, what is the maximum kinetic energy of the photoelectrons?

Prashant Kotian · Accepted Answer

Correct answer: C. Einstein's equation: E = hv - W. At 2v: E_new = h(2v) - W = (hv - W) + hv = E + hv.

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