The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water

Question

The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :

(A) P2 > P1 > P3
(B) P1 > P2 > P3
(C) P2 > P3 > P1
(D) P3 > P1 > P2

Prashant Kotian · Accepted Answer

Correct answer: A. utions is : (1) P2 > P1 > P3 (2) P1 > P2 > P3 (3) P2 > P3 > P1 (4) P3 > P1 > P2 Ans. (1) Sol. p = iCRT P1 = 1 × 10 R T 180 ´ ´ (For Glucose) P2 = 1 × 10 R T 60 ´ ´ (For Urea) P3 = 1 × 10 R T 342 ´ ´ (For Sucrose) \ P2 > P1 > P3

💡 Solution & Explanation

Practice 22,000+ questions like this