See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

rG° = rH°  T  rS° rS° = 2  81 – 4  24 – 3  205 J/mol  rH° =  2258.1 kJ/mol rH° = 2  fH° (Cr2O3,s)   f 2 3 2258.1 H Cr O ,s 1129.05 kJ / mol 2     