JEE Mains Chemistry Past PapershardNUMERICAL

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to 0 xma h . JEE Mains Chemistry Past Papers Chemistry Question

Question

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to 0 xma h . The value of 10 x is ________. (a0 is radius of Bohr's orbit) (Nearest integer) [Given : = 3.14] gkbMªkstu ijek.kq dh f}rh; cksj d{kk esa bysDVªkWu dh xfrt ÅtkZ 0 xma h ds cjkcj gSA 10 x dk eku gS ________. ¼fudVre iw.kk±d esa½ ¼ (a0 cksj d{kk dh f=kT;k gS½A [fn;k gS% = 3.14]

Answer: .

💡 Solution & Explanation

x = 16 8 2   = 32 2 = 32 (3.14)2 = 315.5072 10x = 315.5072

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