JEE Mains Chemistry Past PapershardNUMERICAL

A(g) → 2B(g) + C(g) is a first order reaction. The initial pressure of the system was found to be 80JEE Mains Chemistry Past Papers Chemistry Question

Question

A(g) → 2B(g) + C(g) is a first order reaction. The initial pressure of the system was found to be 800 mm Hg which increased to 1600 mm Hg after 10 min. The total pressure of the system after 30 min will be ________mm Hg. (Nearest integer)

Answer: .

💡 Solution & Explanation

A(g)  2B(g) + C(g) t = 0 – – t = (10 min) 800 – P 2P P PT = 800 – P + 2P + P = 800 + 2P = 1600 So P = 400 mm So 1 t = 10 min Given time 30 min | JEE(Main) 2023 | DATE : 13-04-2023 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 8 So for Ist order Reaction Ct = n ) ( C n = 10 2   t t ; n = number of half life Ct = 3) ( 800 = 100 mm of Hg So after 30 min P = 700 mm PA = 800 – 700 = 100, PB = 1400, PC = 700 PT of reaction mixture = 100 + 1400 + 700 = 2200 mm of Hg

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