MX is a sparingly — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

o o sp X /MX(s)/M M /M 0.0591 E E logK n     = 0.79 + 0.059 log 10 –10 = 0.79 – 0.59 = 0.20 V = 200 mV ALLEN