Correct answer: 15. 2 1 1 2 V 3 2 1 a b c 1 4 2            1 15v  2 1 V 15 V 

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 15

💡 Solution & Explanation

2 1 1 2 V 3 2 1 a b c 1 4 2            1 15v  2 1 V 15 V 

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