25 mL of an aqueous — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

25 ml KCl v/s 20mL of 1M AgNO3 Molarity of KCl = 1 20 = 4 M = L mol . 1L solution has 0.8 mol KCl 1L  1000 g solution mass of KCl = 0.8 × 74.5 = 59.6 ~ 60 mass of solvent  1000 – 60 = 940 g = 0.940 kg Tf = Kf mi = 3.40 ~ 3