JEE Mains Chemistry Past PapershardNUMERICAL

Two reactions are given below: 2 3 822 (g) (s) s Fe O Fe O , Hº – kJ / mol 1 2 (g) (g) s C O CO , HºJEE Mains Chemistry Past Papers Chemistry Question

Question

Two reactions are given below: 2 3 822 (g) (s) s Fe O Fe O , Hº – kJ / mol 1 2 (g) (g) s C O CO , Hº – kJ / mol Then enthalpy change for following reaction 3 2 (s) (s) (g) s C Fe O Fe CO

Answer: .

💡 Solution & Explanation

 2 3 822     (g) (s) s Fe O Fe O , Hº – kJ / mol ……(1)  1 2     (g) (g) s C O CO , Hº – kJ / mol ……(2)  3 2    (s) (s) (g) s C Fe O Fe CO ,   H ? (3) = 3 × (2) – (1) H3 = 3 ×H2 –H1 = 3(–110) + 822 = 492 kJ/mole $//(1® 6 Final JEE-Main Exam January, 2024/30-01-2024/E

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