See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 ; 6900 / HA NaOH NaA H O cal eg     2 ; 2900 / HB NaOH NaB H O cal eg     Let x eq of NaOH react with HA and y eg NaOH react with HB  1 6900 2900 3900 1/ 4 3 / 4 : 1: 3 1 3 4 x y x x y x y x y x y              