See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1: Identify the parent chain/ring. The compound contains a cyclohexane ring, so the parent name is 'cyclohexane'. Step 2: Identify all functional groups on the ring. - At one carbon: a carboxylic acid group (-CO2H), also written as -COOH - Adjacent carbon (next position): a ketone (C=O) as part of the ring, making it an oxo substituent - Two carbons away (para-like position): an aldehyde group (-CHO), called 'formyl' as a substituent Step 3: Apply IUPAC priority rules for numbering. The principal characteristic group (highest priority suffix group) is the carboxylic acid (-COOH), which gets the lowest possible locant. Assign C1 to the carbon bearing -COOH. Step 4: Number the ring to give the next substituents the lowest locants. Going around the ring from C1 (COOH): C2 bears the oxo (=O) group (ketone), and C4 bears the formyl (-CHO) group. Step 5: Assemble the name. - Parent: cyclohexane - Principal group as suffix: carboxylic acid → 'cyclohexane-1-carboxylic acid' - Ketone as prefix: 2-oxo - Aldehyde as prefix: 4-formyl - Full name: 4-formyl-2-oxocyclohexane-1-carboxylic acid Step 6: Verify locants. C1 = COOH, C2 = oxo (=O), C4 = formyl (CHO). The set {1,2,4} is the lowest possible, confirming the numbering is correct. Therefore, the correct answer is 4-formyl-2-oxocyclohexane-1-carboxylic acid.