AITS & Test SerieshardNUMERICAL

See imageAITS & Test Series Chemistry Question

Question

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Answer: 120

💡 Solution & Explanation

   2 2 3 4Fe s 3O g 2Fe O s 40 moles 20 moles   So, 40 moles of Fe will give up 120 moles of electrons to form 20 moles of 2 3 Fe O . For More Material Join: @JEEAdvanced_2025 AITS-FT-IX-PCM(Sol.)-JEE(Main)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12 Mathematics PART – C SECTION – A

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