The ionization energy will be higher when the electron is removed from : — Periodic Table and Periodicity Chemistry Question

💡 Solution & Explanation

Step 1: For any given shell (same principal quantum number n), the penetration power of orbitals decreases in the order s > p > d > f. Step 2: An orbital with higher penetration power is closer to the nucleus and experiences a stronger attraction, holding its electrons more tightly. Step 3: Consequently, removing an electron from an s-orbital requires the highest energy compared to p, d, or f orbitals of the same shell.