The first, second and third ionisation energies (E1, E2 and E3) for an element are 7 eV, 12.5 eV and β Periodic Table and Periodicity Chemistry Question
Question
The first, second and third ionisation energies (E1, E2 and E3) for an element are 7 eV, 12.5 eV and 42.5 eV respectively. The most stable oxidation state of the element will be:
Answer: D
π‘ Solution & Explanation
Step 1: Examine the differences between successive ionization energies: IE2 - IE1 = 5.5 eV, whereas IE3 - IE2 = 30 eV. Step 2: There is an exceptionally large energy jump between the second and third ionization energies, indicating that the third electron must be removed from a stable, filled inner shell core. Step 3: This indicates that the element has two valence electrons, making the +2 oxidation state highly stable.
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes