For a photochemical reaction, A → B, 1 × 10^-5 moles of 'B' were formed on absorption of 6.626 × 10^ — Atomic Structure Chemistry Question

💡 Solution & Explanation

E_abs = 6.626 J. E per photon = hc/λ = 5.52 × 10^-19 J. N photons = 6.626 / (5.52 × 10^-19) = 1.2 × 10^19. N molecules B = 1 × 10^-5 × 6.022 × 10^23 = 6.022 × 10^18. Q.E. = 6.022 × 10^18 / 1.2 × 10^19 = 0.5.