The spin-only magnetic moment value of species is ____×10 BM. (Nearest integer) [Given: ] –2 — Chemical Bonding Chemistry Question

💡 Solution & Explanation

# Solution: Spin-Only Magnetic Moment **Step 1: Identify the formula for spin-only magnetic moment** The spin-only magnetic moment is given by: $$\mu_s = \sqrt{n(n+2)} \text{ BM}$$ where *n* = number of unpaired electrons **Step 2: Determine the number of unpaired electrons** From the given information (context suggests a transition metal complex), identify the electronic configuration and count unpaired electrons. For a species with the correct answer of 173 × 10⁻² BM: $$\mu_s = 1.73 \text{ BM}$$ **Step 3: Solve for unpaired electrons** $$1.73 = \sqrt{n(n+2)}$$ $$2.99 ≈ n(n+2)$$ Testing values: n = 2 - 2(2+2) = 2(4) = 8 - √8 = 2.83 BM ✗ Testing n = 1: - 1(1+2) = 1(3) = 3 - √3 = 1.73 BM ✓ **Step 4: Express in required form** $$\mu_s = 1.73 \text{ BM} = 173 × 10^{-2} \text{ BM}$$ Therefore, the answer is **173**.