Flask with greater collision number of the molecules — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

The collision frequency between molecules z11 ∝ d^2 × (N/V)^2 × √(T/M). Since N/V ∝ 1/M, z11 ∝ d^2 × √(T) / M^2.5. For $H_2$ (A): 1^2 × √300 / 2^2.5 = 17.32 / 5.66 = 3.06. For $CH_4$ (B): 2^2 × √600 / 16^2.5 = 4 × 24.5 / 1024 = 0.096. Clearly, Flask A has the greatest collision number.