In biological cells that have a plentiful supply of , glucose is oxidized completely to and by a pro — Thermodynamics and Thermochemistry Chemistry Question
Question
In biological cells that have a plentiful supply of $O_2$, glucose is oxidized completely to $CO_2$ and $H_2O$ by a process called aerobic oxidation. Muscle cells may be deprived of $O_2$ during vigorous exercise and, in that case, one molecule of glucose is converted to two molecules of lactic acid, CH3CH(OH)COOH, by a process called anaerobic glycolysis.<br>C6H12O6(s) + 6$O_2$(g) → 6$CO_2$(g) + 6$H_2O$(l); ΔH° = -2880 kJ/mol<br>C6H12O6(s) → 2CH3CH(OH)COOH(s); ΔH° = +2530 kJ/mol<br>Which of the following statements is true regarding aerobic oxidation and anaerobic glycolysis with respect to energy change as heat?
💡 Solution & Explanation
The biological energy advantage of a process is determined by how much energy (heat) it releases (highly exothermic is highly favorable).<br>- Aerobic oxidation releases 2880 kJ/mol of glucose (ΔH° = -2880 kJ/mol).<br>- Anaerobic glycolysis is printed as endothermic (ΔH° = +2530 kJ/mol).<br>Therefore, aerobic oxidation releases more energy by:<br>ΔE = -2880 - (+2530) = -5410 kJ/mol.<br>This means aerobic oxidation has a biological energy advantage of 5410 kJ/mol over anaerobic glycolysis.