JEE Mains Chemistry Past PapershardNUMERICAL

The rate of a reaction decreased by 3.555 times when the temperature was changed from 40°C to 30°C. JEE Mains Chemistry Past Papers Chemistry Question

Question

The rate of a reaction decreased by 3.555 times when the temperature was changed from 40°C to 30°C. The activation energy (in kJ mol–1) of the reaction is_________ Take; R = 8314 J mol–1 K–1 In 3.555 = 1.268

Answer: .

💡 Solution & Explanation

      2 k k log = R . Ea        1 T T   . log = R . Ea          1 1 1.268 × 8.314 × 303 × 313 = 10 Ea So, Ea = 100 kJ

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