The rate of a reaction decreased by 3.555 times when the temperature was changed from 40°C to 30°C. — JEE Mains Chemistry Past Papers Chemistry Question
Question
The rate of a reaction decreased by 3.555 times when the temperature was changed from 40°C to 30°C. The activation energy (in kJ mol–1) of the reaction is_________ Take; R = 8314 J mol–1 K–1 In 3.555 = 1.268
Answer: .
💡 Solution & Explanation
2 k k log = R . Ea 1 T T . log = R . Ea 1 1 1.268 × 8.314 × 303 × 313 = 10 Ea So, Ea = 100 kJ
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