See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let x tan , y tan            2 2 x y 1 xy 1 x 1 y        2 2 tan tan 1 tan tan sec sec             sin cos      1 sin 2 2 2    Thus, required range is 1 1 , 2 2        . For More Material Join: @JEEAdvanced_2024