A solution is prepared by dissolving 0.3 g of a non- volatile non-electrolyte solute 'A' of molar mass 60 g mol –1 and 0.9 g of a non-volatile non- electrolyte solute 'B' of molar mass 180 g mol –1 in

Question

A solution is prepared by dissolving 0.3 g of a non- volatile non-electrolyte solute 'A' of molar mass 60 g mol –1 and 0.9 g of a non-volatile non- electrolyte solute 'B' of molar mass 180 g mol –1 in 100 mL H2O at 27°C. Osmotic pressure of the solution will be [Given : R = 0.082 L atm K –1 mol –1]

(A) 1.23 atm
(B) 2.46 atm
(C) 0.82 atm
(D) 1.47 atm

Prashant Kotian · Accepted Answer

Correct answer: B. ution will be [Given : R = 0.082 L atm K –1 mol –1] (1) 1.23 atm (2) 2.46 atm (3) 0.82 atm (4) 1.47 atm Ans. (2) Sol. Mass of solute 'A' = 0.3 g Moles of solute 'A' = 0.3g 60g / mol  mol Mass of solute 'B' = 0.9 g ALLEN  Moles of solute 'B' = 0.9gm 180g / mol  mol Total molarity of all solutes = 2 / 200 1000 M 10    = 1 × 0.082 × 300  = 2.46 atm.

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