Correct answer: 00006.00. 4 2 3 2 XeF H O Xe XeO HF O 'A' 'B'      Oxidation state of Xe = 0 Oxidation of Xe in XeO3 = +6

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 00006.00

💡 Solution & Explanation

4 2 3 2 XeF H O Xe XeO HF O 'A' 'B'      Oxidation state of Xe = 0 Oxidation of Xe in XeO3 = +6

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