To very good approximations, the cooling of a hot body to room temperature follows first-order kinetics (in this case, temperature difference Δθ is changing instead of concentration). If the rate cons

Question

To very good approximations, the cooling of a hot body to room temperature follows first-order kinetics (in this case, temperature difference Δθ is changing instead of concentration). If the rate constant for a body is 0.04 s⁻¹, then [ln 2 = 0.7, ln(323/25) = 2.6]

Prashant Kotian · Accepted Answer

Correct answer: B,C. Using Newton's cooling integrated form: t = ln(Δθ_0/Δθ_t)/k. For 323°C→25°C: t = 2.6/0.04 = 65 s. For 1192K→298K (same Δθ ratio but different reference): t = 35 s.

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