Consider the following complex ions P = [FeF6]3– Q = [V(H2O) 6]2+ R = [Fe(H2O)6] 2+ The correct orde — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider the following complex ions P = [FeF6]3– Q = [V(H2O) 6]2+ R = [Fe(H2O)6] 2+ The correct order of the complex ions, according to their spin only magnetic moment values (in B.M.) is : (A) R < Q < P (B) R < P< Q (C) Q < R < P (D) Q < P < R
Answer: C
💡 Solution & Explanation
[FeF6]3– : Fe+3 : [Ar] 3d5 F : Weak field Ligand No. of unpaired electron's = 5 = 5(5 2) = 35 BM [V(H2O)6]+2 : V+2 : 3d3 No. of unpaired electron's = 3 = 3(3 2) = 15 BM [Fe(H2O)6]+2 : Fe+2 : 3d6 H2O : Weak field Ligand No. of unpaired electron's = 4 = 4(4 2) = 24 BM
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