The molar ratio of dimer to monomer for 0.1 M acetic acid in water (neglecting the dissociation of a — Ionic Equilibrium Chemistry Question

💡 Solution & Explanation

In water, the equilibrium constant for dimerization is K = 3.6 × 10^-2 M^-1. Since K is very small, we can approximate [M] approx C = 0.1 M. Then, dimer concentration [D] approx K × [M]^2 = 0.036 × (0.1)^2 = 3.6 × 10^-4 M. Molar ratio [D]/[M] = 3.6 × 10^-4 / 0.1 = 3.6 × 10^-3 = 36 / 10000 = 9 / 2500.