See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

For option (A) P = 80XA + 240 XB = 80 XA + 240 (1 - XA) = 80 XA + 240 - 240 XA = 240 + XA(80 - 240) = 240 – 160 XA  V.P of solution is less than 240 mm Hg which is V.P of pure(B) For option (B) P = 80XA + 240 XB = 80(1 – XB) + 240 XB = 80 – 80 XB + 240 XB = 80 + (240 – 80)XB = 80 + 160 XB  V.P of solution is more than 80 mm Hg which is the V.P of pure(A) For option (C) P = 80XA + 240XB For pure (A), XA = 1 and XB = 0 V.P of pure (A) = 80 mm Hg Similarly  V.P of pure (B) = 240 mm Hg. AITS-FT-VIII-(Paper-1)-PCM-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6