Combustion of 1 mole of benzene is expressed at C6H6(1) + ( ) ( ) ( ) 2 15 O g CO g 3H O 1 . → + The — JEE Mains Chemistry Past Papers Chemistry Question
Question
Combustion of 1 mole of benzene is expressed at C6H6(1) + ( ) ( ) ( ) 2 15 O g CO g 3H O 1 . → + The standard enthalpy of combustion of 2 mol of benzene is – 'x' kJ. x = ______. (1) standard Enthalpy of formation of 1 mol of C6H6(1), for the reaction 6C(graphite) + 3H2(g) → C6H6(1) is 48.5 kJ mol –1. (2) Standard Enthalpy of formation of 1 mol of CO2(g), for the reaction C(graphite) + O2(g) → CO2(g) is –393.5 kJ mol –1. (3) Standard and Enthalpy of formation of 1 mol of H2O(1), for the reaction H2(g) + ( ) 1 O g → H2O(1) is –286 kJ mol –1.
💡 Solution & Explanation
6C(graphite)+3H2(g) → C6H6(); ∆H = 48.5 kJ/mol C(graphite)+O2(g)→ CO2(g); ∆H = –393.5 kJ/mol ( ) ( ) g 1 H g + → H2O() ; ∆H = – 286 kJ/mol equation –(1) × 1 + (2) × 6 + (3) × 3 – 48.5 –6 × 393.5 – 3 × 286 = – 3267.5 kJ for 1 mol = – 6535 kJ for 2 mol Ans. 6535 kJ