Combustion of 1 mole of benzene is expressed at C6H6(1) + ( ) ( ) ( ) 2 15 O g CO g 3H O 1 . β + The β JEE Mains Chemistry Past Papers Chemistry Question
Question
Combustion of 1 mole of benzene is expressed at C6H6(1) + ( ) ( ) ( ) 2 15 O g CO g 3H O 1 . β + The standard enthalpy of combustion of 2 mol of benzene is β 'x' kJ. x = ______. (1) standard Enthalpy of formation of 1 mol of C6H6(1), for the reaction 6C(graphite) + 3H2(g) β C6H6(1) is 48.5 kJ mol β1. (2) Standard Enthalpy of formation of 1 mol of CO2(g), for the reaction C(graphite) + O2(g) β CO2(g) is β393.5 kJ mol β1. (3) Standard and Enthalpy of formation of 1 mol of H2O(1), for the reaction H2(g) + ( ) 1 O g β H2O(1) is β286 kJ mol β1.
π‘ Solution & Explanation
6C(graphite)+3H2(g) β C6H6(ο¬); βH = 48.5 kJ/mol C(graphite)+O2(g)β CO2(g); βH = β393.5 kJ/mol ( ) ( ) g 1 H g + ο£§β H2O(ο¬) ; βH = β 286 kJ/mol equation β(1) Γ 1 + (2) Γ 6 + (3) Γ 3 β 48.5 β6 Γ 393.5 β 3 Γ 286 = β 3267.5 kJ for 1 mol = β 6535 kJ for 2 mol Ans. 6535 kJ