When the products released by explosion of 0.04 mole of nitroglycerine were placed in a 821 ml flask and the flask was cooled to -23°C, product 'A' solidified and the pressure inside the flask was 4.7

Question

When the products released by explosion of 0.04 mole of nitroglycerine were placed in a 821 ml flask and the flask was cooled to -23°C, product 'A' solidified and the pressure inside the flask was 4.75 atm. How many moles of A were present and what is its likely identity? Neglect the volume of solid formed.

Prashant Kotian · Accepted Answer

Correct answer: C. After cooling to 250 K (T = -23°C), the remaining gas moles are: n_remaining = PV / RT = 4.75 × 0.821 / (0.0821 × 250) = 3.90 / 20.525 = 0.19 mol. Since the total initial moles of gas products was 0.29 mol, the moles of A that solidified is 0.29 - 0.19 = 0.10 mol. This substance is , which has a high boiling point and easily solidifies/condenses upon cooling.

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