See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

      2 6 2 3 3 Lone pair in TeBr , IF , SNF and XeF    are 1, 2, 0 and 3 respectively. Hence, x = 6. Diamagnetic species are 2 2 2 2 2 2 4 3 3 6 Li , C , O , K O, N O , B N H  . Note: Be2 does not exist so we can’t say it is paramagnetic or diamagnetic species. Hence, y = 6. x y 6 2   .