(PhCOO) HBr Ph CH CH Product Consider the above reaction A. The reaction proceeds through a more stable radical intermediate. B. The role of peroxide is to generate H (Hydrogen radical). C. During thi

Question

(PhCOO) HBr Ph CH CH Product Consider the above reaction A. The reaction proceeds through a more stable radical intermediate. B. The role of peroxide is to generate H (Hydrogen radical). C. During this reaction, benzene is formed as a biproduct. D. 1-Bromo-2-phenylethane is fanned as the minor product. E. The same reaction in absence of peroxide proceeds via carbocation intermediate. Identify the correct statements. Choose the correct answer from the options given below:

(A) A & E Only
(B) A, B & D Only
(C) C, D & E Only
(D) A, C & E Only

Prashant Kotian · Accepted Answer

Correct answer: D. Ph–CH=CH2 (PhCOO) HBr  Ph–CH2–CH2–Br Anti Markovnikov addition  Reaction follow radical addition in presence of peroxide In absence of peroxide follow carbocation mechanism Benzene also formed O Ph–C–O–O–C–Ph  2Ph–C–O O O  O Ph–C–O  Ph + CO2  Ph + HBr  Ph – H + Br  Ph–CH = CH2 + Br  Ph–CH–CH2–Br  HBr Ph–CH2–CH2–Br

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