Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g) and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2(s) is reacted with excess aqueous HCl solution ? (Given Molar mass i

Question

Aqueous HCl reacts with MnO2(s) to form MnCl2(aq), Cl2(g) and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2(s) is reacted with excess aqueous HCl solution ? (Given Molar mass in g mol –1 Mn = 55, Cl = 35.5, O = 16, H = 1)

(A) 7.1
(B) 71
(C) 21.3
(D) 14.2

Prashant Kotian · Accepted Answer

Correct answer: A. MnO2 + 4HCl  MnCl2 + Cl2 + 2H2O 8.7 87 Excess = 0.1 mole 0.1 mole Wt. of Cl2 obtained = 0.1 × 71 = 7.1 g

💡 Solution & Explanation

Practice 22,000+ questions like this