See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

By observing given reactions, we find n factor for KBrO3 is 5 and 6 respectively. Initial moles of KBrO3 = 20 × -3 1×10 6  Equivalent of KBrO3 =       -3 1 20× ×10 ×5 6 = 16.6 × 10–3 Equivalents of AsO2 – reacted with excess of KBrO3 = -3 1