See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1: Identify the substituents on the benzene ring. From the structural drawing, the benzene ring bears three bromine (Br) atoms and three chlorine (Cl) atoms at alternating and adjacent positions. Step 2: Number the ring to give the lowest possible locants. Assign numbering starting at one of the bromine-bearing carbons and proceed around the ring to minimize locant set. Step 3: Reading the structure, the substituents are placed as follows: Br at C1 (top), Br at C2 (top-right), Cl at C3 (bottom-right), Cl at C4 (bottom), Br at C5 (bottom-left), Cl at C6 (top-left). This gives Br at positions 1, 2, 5 and Cl at positions 3, 4, 6. Step 4: Verify this numbering gives the lowest locant set. The set {1,2,3,4,5,6} is fully substituted; comparing alphabetically, Br comes before Cl, so we cite Br first: 1,2,5-tribromo, then Cl: 3,4,6-trichloro. Step 5: Construct the IUPAC name by listing substituents alphabetically (bromo before chloro) with their locants: 1,2,5-tribromo-3,4,6-trichlorobenzene. Therefore, the correct answer is 1,2,5-tribromo-3,4,6-trichlorobenzene.