See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Area 1 ab 2  AD: y x 3   BE : y 2x 4   solve   G 1,2  acute angle  between the median is 1 2 1 2 m m tan 1 m m    2 1 1 tan tan 1 2 3      now   o o 180 90 360    o 90    cot tan   tan tan 3 1 tan tan        or   2 2 2b 2a 2 a b a b 3 9 2b 2a ab 1 . a b        9ab 2 360    1ab 400 2   Area = 400 sq. units A C B (–1, 2) F G  90o  a/2 D (m2 = 2) (m1 = 1) b/2 b/2 a/2  E  