X of enthanamine was subjected to reaction with NaNO2/HCl followed by hydrolysis to liberate N2 and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is ____ g.

Question

Prashant Kotian · Accepted Answer

Correct answer: .. CH3—CH2—NH2 NaNO2 + HCl CH3—CH2—N2Cl ⊕ Θ HOH CH3—CH2—OH + N2 + HCl (g) 0.2 mole 0.2 mole MW of ethanamine = 45 45 × 0.2 = 9 gm

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