See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol. (A) m = 2, 2   , n = 3 (B) Ne = 1s2 2s2 2p6 (C) 3d = 3p (D) 2 1 E n  n = 3 Third shell in hydrogen atom 3s = 3p = 3d Ans. 9 orbitals. AITS-PT-I (Paper-1)-PCM (Sol.)-JEE(Advanced)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7