Read the following short write up and answer subsequent questions based on observations(A) to (J). [ β Qualitative and Quantitative Analysis Chemistry Question
Question
Read the following short write up and answer subsequent questions based on observations(A) to (J). [SEE DIAGRAM] Flowchart summary: AgNO3 -> white ppt. soluble in aq. NH3 + green coloured solution of a compound (A) green coloured solution of a compound (A) --(NaOH in excess)--> coloured ppt. soluble in excess NaOH green coloured solution of a compound (A) --(KOH/H2O2)--> yellow coloured solution (B) yellow coloured solution (B) --(H2SO4)--> orange coloured solution (C) orange coloured solution (C) --(NH4Cl)--> orange coloured solution of compound (D) --(Crystallization, Ξ)--> gas (G) + H2O + Residue (H) gas (G) --(Li, Ξ)--> solid (I) --(H2O)--> gas (J) --(CuSO4(aq))--> deep blue solution (C) in solid state --(KCl + conc. H2SO4)--> red gas (E) --(KOH(aq))--> (B) --(CH3COOH/Pb2+)--> yellow ppt. (F)
![Chemistry diagram for: Read the following short write up and answer subsequent questions based on observations(A) to (J). [SEE DIAGRAM] Flowcha](/_next/image?url=https%3A%2F%2Furywdhpqdpvmqzlenttu.supabase.co%2Fstorage%2Fv1%2Fobject%2Fpublic%2Fquestion-images%2Fvkj%2Fch10_l3_Q002.png&w=1920&q=75)
π‘ Solution & Explanation
Step 1: When NaOH is added to the mixture containing Al3+, Zn2+, and Cu2+, all of them initially form hydroxide precipitates. Step 2: Since Al(OH)3 and Zn(OH)2 are amphoteric, they dissolve in excess NaOH to form soluble aluminate ([Al(OH)4]-) and zincate ([Zn(OH)4]2-) complexes. Step 3: In contrast, Cu(OH)2 is a basic hydroxide and remains insoluble as a characteristic blue precipitate, allowing both the identification and separation of Cu2+ in one step, matching option (c).