The RMS speed of oxygen molecules in a gas is V. If the temperature is doubled and the oxygen molecu — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

rms speed u_rms = √(3rt/m). given: t2 = 2t and the molar mass of the particles becomes m2 = m/2 because o2 molecules dissociate into o atoms. thus, u_rms2 = √(3r(2t)/(m/2)) = √(4 × 3rt/m) = 2 × u_rms = 2v.