Correct answer: 19.75.   dE S nF dT 5 2 96500 5 10    1 2 5 965 1000    2 965 10     G nFE 2 96500

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 19.75

💡 Solution & Explanation

  dE S nF dT 5 2 96500 5 10    1 2 5 965 1000    2 965 10     G nFE 2 96500

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