Match List I with List II List I Coordination Complex List II Number of unpaired electrons A. [Cr(CN — JEE Mains Chemistry Past Papers Chemistry Question
Question
Match List I with List II List I Coordination Complex List II Number of unpaired electrons A. [Cr(CN)6]3– I. B. [Fe(H2O)6]2+ II. C. [Co(NH3)6]3+ III. D. [Ni(NH3)6]2+ IV. Choose the correct answer from the options given below: (A) A-II, B-I, C-IV, D-III (B) A-II, B-IV, C-I, D-III (C) A-IV, B-III, C-II, D-I (D) A-III, B-IV, C-I, D-II
💡 Solution & Explanation
complex ion Configuration number of unpaired electron (i) Cr(CN)6]3– 24Cr3+ = 3d3 1,1,1 g 2t , , g e (ii) [Fe(H2O)6]2+ 26Fe2+ = 3d6 1, g 2t , 1,1 g e (iii) [Ni(NH3)6]2+ 28Ni2+ = 3d8 ,2 ,2 g 2t , 1,1 g e (iv) [Co(NH3)6]3+ 27Co3+ = 3d6 ,2 ,2 g 2t , , g e | JEE(Main) 2023 | DATE : 08-04-2023 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 8