See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

InOH In OH        b In OH K InOH          Also   b In pOH pK log InOH        At pH = 3.3, pOH = 14 – 3.3 = 10.7, the indicator will be sufficiently ionized to give the colour solely due to Inion. Hence,   b In