Some CO2 gas was kept in a sealed container at a pressure of 1 atm and at 273 K. This entire amount — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Let moles of CO2 = a Excess moles of Ca(OH)2 = a Ca(OH)2 + CO2  CaCO3 + H2O 2) OH ( Ca eq = HCl eq a × 2 = 0.1 × 1000 40 × 1 or a = 2 × 10–3 mol Volume of CO2 = 2 × 10–3 × 22400 = 44.8 cm3 | JEE(Main) 2025 | DATE : 22-01-2025 (SHIFT-1) | PAPER-1 | CHEMISTRY PAGE # 6