See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let, x ml of 2.0 M NaOH solution be added, then   3 4 2 4 2 H PO NaOH NaH PO H O millimoles 10 2x 0 0 0 2x 10         2 4 2 4 2 NaH PO NaOH Na HPO H O 10 2x 10 0 10 2x 10 0 2x 10        = 20 – 2x So, 2x 10