Correct answer: 941000. 37.35 2 200 p C jK mol       Also 3 , 2 p C x R         where x = atomicity. 3

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 941000

💡 Solution & Explanation

37.35 2 200 p C jK mol       Also 3 , 2 p C x R         where x = atomicity. 3

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry